Wie erweitert man (xy) ^ 3 ?
Antworten:
= x^3-3x^2y+3xy^2-y^3
Erläuterung:
(x-y)(x-y). = x^2-xy-xy+y^2
=x^2-2xy+y^2
=(x^2-2xy+y^2)(x-y)
= x^3-x^2y-2x^2y+2xy^2+xy^2-y^3
= x^3-3x^2y+3xy^2-y^3
= x^3-3x^2y+3xy^2-y^3
(x-y)(x-y). = x^2-xy-xy+y^2
=x^2-2xy+y^2
=(x^2-2xy+y^2)(x-y)
= x^3-x^2y-2x^2y+2xy^2+xy^2-y^3
= x^3-3x^2y+3xy^2-y^3