Wie wird #2x ^ {2} + 3x = 5 # berücksichtigt?

Antworten:

#(x-1)(2x+5)=0#

Erläuterung:

#"rearrange equation into standard form"#

#rArr2x^2+3x-5=0larrcolor(blue)"in standard form"#

#"factor the quadratic using the a-c method"#

#"the factors of - 10 which sum to + 3 are + 5 and - 2"#

#2x^2-2x+5x-5=0larrcolor(blue)"split the middle term"#

#color(red)(2x)(x-1)color(red)(+5)(x-1)=0larrcolor(blue)"factor by grouping"#

#"take out a common factor "(x-1)#

#(x-1)(color(red)(2x+5))=0larrcolor(blue)"factored form"#

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