Wie unterscheidet man 1 + cos ^ 2 (x) ?
Antworten:
-sin2x
Erläuterung:
"differentiate using the "color(blue)"chain rule"
"given "y=f(g(x))" then"
dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"
y=1+(cosx)^2
dy/dx=2cosx xxd/dx(cosx)
color(white)(dy/dx)=-2sinxcosx=-sin2x