Wie binde ich (1 / x ^ 4) dx ein?
Antworten:
int 1/x^4color(white)(.)dx = -1/(3x^3) + C
Erläuterung:
Beachten Sie, dass:
d/(dx) 1/x^3 = d/(dx) x^(-3) = -3 x^(-4) = -3(1/x^4)
Damit:
int 1/x^4color(white)(.)dx = -1/(3x^3) + C
int 1/x^4color(white)(.)dx = -1/(3x^3) + C
Beachten Sie, dass:
d/(dx) 1/x^3 = d/(dx) x^(-3) = -3 x^(-4) = -3(1/x^4)
Damit:
int 1/x^4color(white)(.)dx = -1/(3x^3) + C