Was ist die Ableitung von cosec x?
Antworten:
#-cotxcscx#
Erläuterung:
#"differentiate using the "color(blue)"chain rule"#
#"given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#"here "y=cscx=1/sinx=(sinx)^-1#
#rArrdy/dx=-(sinx)^-2xxd/dx(sinx)#
#color(white)(rArrdy/dx)=-cosx/(sin^2x)#
#color(white)(rArrdy/dx)=-cosx/sinx xx1/sinx#
#color(white)(rArrdy/dx)=-cotxcscx#