Dezember 21, 2019

von Karee

Wie löst man für h in $V = πr ^ 2h$ ?

Antworten:

$h=V/(pir^2)$

Erläuterung:

Consider the simple equation $2x=6$

To solve for x, we divide both sides of the equation by 2

$rArr(cancel(2) x)/cancel(2)=6/2rArrx=3$

In a similar way, divide both sides by the multiplier of h.

$rArrpir^2h=V$

divide both sides by $pir^2$

$(cancel(pir^2) h)/cancel(pir^2)=V/(pir^2)$

$rArrh=V/(pir^2)$