Wie löst man für h in # V = πr ^ 2h #?

Consider the simple equation #2x=6#

To solve for x, we divide both sides of the equation by 2

#rArr(cancel(2) x)/cancel(2)=6/2rArrx=3#

In a similar way, divide both sides by the multiplier of h.

#rArrpir^2h=V#

divide both sides by #pir^2#

#(cancel(pir^2) h)/cancel(pir^2)=V/(pir^2)#

#rArrh=V/(pir^2)#