Y = x ^ 2-6x + 7 in Scheitelpunktform?
Y = x ^ 2-6x + 7 in Scheitelpunktform? Antworten: #y=(x-3)^2-2# Erläuterung: #“the equation of a parabola in „color(blue)“vertex form“# is. #color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))# #“where „(h,k)“ are the coordinates of the vertex and a“# #“is a multiplier“# #“given the parabola in „color(blue)“standard form“;y=ax^2+bx+c# #“then the x-coordinate of the vertex is“# #•color(white)(x)x_(color(red)“vertex“)=-b/(2a)# #y=x^2-6x+7″ is in standard form“# #“with … Weiterlesen