Jacenta

Y = x ^ 2-6x + 7 in Scheitelpunktform? Antworten: `y=(x-3)^2-2` Erläuterung: `“the equation of a parabola in „color(blue)“vertex form“` is. `color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))` `“where „(h,k)“ are the coordinates of the vertex and a“` `“is a multiplier“` `“given the parabola in „color(blue)“standard form“;y=ax^2+bx+c` `“then the x-coordinate of the vertex is“` `•color(white)(x)x_(color(red)“vertex“)=-b/(2a)` `y=x^2-6x+7″ is in standard form“` #“with … Weiterlesen