Wie unterscheidet man f (x) = cos ^ 2x ?
Wie unterscheidet man f (x) = cos ^ 2x ? Antworten: f'(x)=-sin2x Erläuterung: differentiate using the color(blue)“chain rule“ color(orange)“Reminder “ color(red)(bar(ul(|color(white)(2/2)color(black)(dy/dx=(dy)/(du)xx(du)/(dx))color(white)(2/2)|))) “Express “ f(x)=cos^2x=(cosx)^2 “let „u=cosxrArr(du)/(dx)=-sinx “then „y=u^2rArr(dy)/(du)=2u rArrdy/dx=2u(-sinx) change u back into terms of x rArrdy/dx=-2sinxcosx color(orange)“Reminder“ sin2x=2sinxcosx rArrdy/dx=-sin2x