Wenn $f (x) = 2 x + 1$ $f (x) = 2x + 1$ und $g (x) = \frac{x - 1}{2}$ $g (x) = (x-1) / 2$ , was ist $f (g (x))$ $f (g (x))$ ?

$= x$ $=x$

$f (g (x)) = 2 \frac{x - 1}{2} + 1$ $f(g(x))=2(x-1)/2+1$
$= x - 1 + 1$ $=x-1+1$
$= x$ $=x$

Wenn f (x) = 2x + 1 f(x)=2x+1f (x) = 2x + 1 und g (x) = (x-1) / 2 g(x)=x−12g (x) = (x-1) / 2 , was ist f (g (x)) f(g(x))f (g (x)) ?