Wie löst man # S = 2pirh + 2pir ^ 2 # für # h #?

#"isolate the term containing h"#

#rArr2pirh=S-2pir^2#

#"divide both sides by "2pir#

#(cancel(2pir) h)/cancel(2pir)=(S-2pir^2)/(2pir)#

#rArrh=(S-2pir^2)/(2pir)#