Wie konvertiert man r = sin (Theta) in eine Rechteckgleichung?

Antworten:

#x^2+(y-1/2)^2=1/4#

Erläuterung:

#"to convert from "color(blue)"polar to rectangular"#

#•color(white)(x)r=sqrt(x^2+y^2)#

#•color(white)(x)y=rsinthetarArrsintheta=y/r#

#r=sintheta#

#r=y/rlarr"multiply both sides by "r#

#r^2=y#

#x^2+y^2-y=0larrcolor(blue)"rectangular equation"#

#"which is the equation of a circle"#

#x^2+(y-1/2)^2=1/4#

#"centre "=(0,1/2)" and radius "=1/2#
graph{(x^2+(y-1/2)^2-1/4)=0 [-10, 10, -5, 5]}

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