Wie konvertiert man r = sin (Theta) in eine Rechteckgleichung?

Antworten:

$x^2+(y-1/2)^2=1/4$

Erläuterung:

$"to convert from "color(blue)"polar to rectangular"$

$•color(white)(x)r=sqrt(x^2+y^2)$

$•color(white)(x)y=rsinthetarArrsintheta=y/r$

$r=sintheta$

$r=y/rlarr"multiply both sides by "r$

$r^2=y$

$x^2+y^2-y=0larrcolor(blue)"rectangular equation"$

$"which is the equation of a circle"$

$x^2+(y-1/2)^2=1/4$

$"centre "=(0,1/2)" and radius "=1/2$
graph{(x^2+(y-1/2)^2-1/4)=0 [-10, 10, -5, 5]}