Wie bewerten Sie `sec (pi / 3)`?

`secx = 1/cosx`

`rArr sec(pi/3) = 1/cos(pi/3)`

Using the `pi/3 , pi/6 , pi/2 " triangle "`

with sides of length 1 ,`sqrt3 " and " 2`

we can obtain the exact value of `cos(pi/3) = 1/2`

`rArr sec(pi/3) = 1/(1/2) = 2`