Wie finden Sie den Wert von #cot (pi / 2) #?
Antworten:
0
Erläuterung:
the cot function may be written as:
# cotx = cosx/sinx #
hence # cot(pi/2) = cos(pi/2)/sin(pi/2) = 0/1 = 0#
0
the cot function may be written as:
# cotx = cosx/sinx #
hence # cot(pi/2) = cos(pi/2)/sin(pi/2) = 0/1 = 0#