Wie rechnen Sie mit: # 2x ^ 2 + 7x + 3 #?
Antworten:
#(x+3)(2x+1)#
Erläuterung:
#"using the a-c method of factorising"#
#"the factors of "2xx3=6#
#"which sum to + 7 are + 6 and + 1"##"split the middle term using these factors"#
#rArr2x^2+6x+x+3larrcolor(blue)"factor by grouping"#
#=color(red)(2x)(x+3)color(red)(+1)(x+3)#
#"take out the common factor "(x+3)#
#=(x+3)(color(red)(2x+1))#
#rArr2x^2+7x+3=(x+3)(2x+1)#