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		<title>Was ist das Integral von # x / (1 + x ^ 2) #?</title>
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		<dc:creator><![CDATA[Renee]]></dc:creator>
		<pubDate>Mon, 02 Mar 2020 18:52:30 +0000</pubDate>
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					<description><![CDATA[Was ist das Integral von # x / (1 + x ^ 2) #? Antworten: #intx/(x^2+1)dx=1/2ln(x^2+1)+C# Erläuterung: Lassen #u(x)=1+x^2" "# dann #" "du(x) =2xdx # #" "# #color(blue)((d(u(x)))/2=xdx)# #" "# Lösen Sie das Integral. #" "# #intx/(x^2+1)dx# #" "# #=intcolor(blue)((d(u(x)))/(2u(x))# #" "# #=1/2int(du(x))/(u(x))# #" "# #=1/2lnabs(u(x))+C# #" "# #=1/2lnabs(x^2+1)+C# #" "# weil #x^2+1&#62;0 " " ... <a title="Was ist das Integral von # x / (1 + x ^ 2) #?" class="read-more" href="https://dieklugeeule.com/was-ist-das-integral-von-x-1-x-2/" aria-label="Mehr dazu unter Was ist das Integral von # x / (1 + x ^ 2) #?">Weiterlesen</a>]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Was ist das Integral von # x / (1 + x ^ 2) #?</h1>
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<h4 class="answerHeader">Antworten:</h4>
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<p>#intx/(x^2+1)dx=1/2ln(x^2+1)+C#</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p>Lassen #u(x)=1+x^2" "# dann #" "du(x) =2xdx #<br />
#" "#<br />
#color(blue)((d(u(x)))/2=xdx)#<br />
#" "#<br />
Lösen Sie das Integral.<br />
#" "#<br />
#intx/(x^2+1)dx#<br />
#" "#<br />
#=intcolor(blue)((d(u(x)))/(2u(x))#<br />
#" "#<br />
#=1/2int(du(x))/(u(x))#<br />
#" "#<br />
#=1/2lnabs(u(x))+C#<br />
#" "#<br />
#=1/2lnabs(x^2+1)+C#<br />
#" "#<br />
weil #x^2+1&gt;0 " " then " " abs(x^2+1)=x^2+1#<br />
#" " #<br />
Deswegen,<br />
#" "#<br />
#intx/(x^2+1)dx=1/2ln(x^2+1)+C#</p>
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