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	<title>Ninette &#8211; Die Kluge Eule</title>
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		<title>Wie finden Sie die Ableitung von # 1 / (2x) #?</title>
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		<dc:creator><![CDATA[Ninette]]></dc:creator>
		<pubDate>Wed, 22 Jan 2020 18:52:16 +0000</pubDate>
				<category><![CDATA[Infinitesimalrechnung]]></category>
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					<description><![CDATA[Wie finden Sie die Ableitung von # 1 / (2x) #? Antworten: #-1/(2x^2)# Erläuterung: Differentiate using the #color(blue)"power rule"# #color(red)(&#124;bar(ul(color(white)(a/a)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(a/a)&#124;)))# Rewrite the function as. #1/(2x)=1/2xx1/x=1/2xxx^-1=1/2x^-1# #rArrd/dx(1/2x^-1)=-1xx1/2x^(-1-1)=-1/2x^-2# #rArrd/dx(1/(2x))=-1/2x^-2=-1/(2x^2)#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie finden Sie die Ableitung von # 1 / (2x) #?</h1>
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<h4 class="answerHeader">Antworten:</h4>
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<p>#-1/(2x^2)#</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p>Differentiate using the #color(blue)"power rule"#</p>
<p>#color(red)(|bar(ul(color(white)(a/a)color(black)(d/dx(ax^n)=nax^(n-1))color(white)(a/a)|)))#</p>
<p>Rewrite the function as.</p>
<p>#1/(2x)=1/2xx1/x=1/2xxx^-1=1/2x^-1#</p>
<p>#rArrd/dx(1/2x^-1)=-1xx1/2x^(-1-1)=-1/2x^-2#</p>
<p>#rArrd/dx(1/(2x))=-1/2x^-2=-1/(2x^2)#</p>
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