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	<title>Maribelle &#8211; Die Kluge Eule</title>
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		<title>Was ist das Integral von # cos ^ 2 (x) #?</title>
		<link>https://dieklugeeule.com/was-ist-das-integral-von-cos-2-x/</link>
		
		<dc:creator><![CDATA[Maribelle]]></dc:creator>
		<pubDate>Thu, 26 Dec 2019 17:37:28 +0000</pubDate>
				<category><![CDATA[Infinitesimalrechnung]]></category>
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					<description><![CDATA[Was ist das Integral von # cos ^ 2 (x) #? Antworten: #int cos(x)^2 dx = x/2 + 1/4 Sin(2 x)+C# Erläuterung: #cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)# Herstellung #alpha=beta-&#62;cos(2alpha) = cos(alpha)^2-sin(alpha)^2# aber #cos(alpha)^2+sin(alpha)^2=1# dann #cos(alpha)^2=( 1+cos(2 alpha))/2# so #int cos(x)^2dx = int( 1+cos(2 x))/2dx = 1/2int dx + 1/2intcos(2x)dx# Endlich #int cos(x)^2 dx = x/2 + 1/4 Sin(2 x)+C#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Was ist das Integral von # cos ^ 2 (x) #? </h1>
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<h4 class="answerHeader">Antworten:</h4>
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<p>#int cos(x)^2 dx = x/2 + 1/4 Sin(2 x)+C#</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p class="gt-block">#cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)#<br />
Herstellung #alpha=beta-&gt;cos(2alpha) = cos(alpha)^2-sin(alpha)^2#<br />
aber #cos(alpha)^2+sin(alpha)^2=1# dann<br />
#cos(alpha)^2=( 1+cos(2 alpha))/2#</p>
<p>so  #int cos(x)^2dx = int( 1+cos(2 x))/2dx = 1/2int dx + 1/2intcos(2x)dx#<br />
Endlich #int cos(x)^2 dx = x/2 + 1/4 Sin(2 x)+C#</p>
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