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	<title>Lorianna &#8211; Die Kluge Eule</title>
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		<title>Wie löst man # sinx-tanx = 0 #?</title>
		<link>https://dieklugeeule.com/wie-lost-man-sinx-tanx-0/</link>
		
		<dc:creator><![CDATA[Lorianna]]></dc:creator>
		<pubDate>Thu, 30 Jan 2020 18:42:23 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
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					<description><![CDATA[Wie löst man # sinx-tanx = 0 #? Antworten: #x = kpi# #x = 2kpi# Erläuterung: sin x - tan x = 0 #sin x - (sinx/cos x) = 0# sin x.cos x - sin x = 0 sin x (cos x - 1) = 0 Jeder Faktor sollte Null sein. ein. sin x = ... <a title="Wie löst man # sinx-tanx = 0 #?" class="read-more" href="https://dieklugeeule.com/wie-lost-man-sinx-tanx-0/" aria-label="Mehr dazu unter Wie löst man # sinx-tanx = 0 #?">Weiterlesen</a>]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie löst man # sinx-tanx = 0 #?</h1>
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<h4 class="answerHeader">Antworten:</h4>
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<p class="gt-block">#x = kpi#<br />
#x = 2kpi#</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p class="gt-block">sin x - tan x = 0<br />
#sin x - (sinx/cos x) = 0#<br />
sin x.cos x - sin x = 0<br />
sin x (cos x - 1) = 0 <br />
Jeder Faktor sollte Null sein.<br />
ein. sin x = 0 <br />
Einheitskreis gibt:<br />
x = 0, #x = pi, and x = 2pi#<br />
Allgemeine Antwort: #x = kpi#<br />
b. cos x - 1 = 0 -&gt; cos x = 1 <br />
#x = 0 + 2kpi = 2kpi#</p>
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