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	<title>Laurene &#8211; Die Kluge Eule</title>
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	<title>Laurene &#8211; Die Kluge Eule</title>
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		<title>Wie beweist man # (1 + sinx) ^ 2 + (1-sinx) ^ 2 = 4 &#8211; 2 cos ^ 2x #?</title>
		<link>https://dieklugeeule.com/wie-beweist-man-1-sinx-2-1-sinx-2-4-2-cos-2x/</link>
		
		<dc:creator><![CDATA[Laurene]]></dc:creator>
		<pubDate>Mon, 16 Mar 2020 18:53:05 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=10431</guid>

					<description><![CDATA[Wie beweist man # (1 + sinx) ^ 2 + (1-sinx) ^ 2 = 4 - 2 cos ^ 2x #? Versuche dies:]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie beweist man # (1 + sinx) ^ 2 + (1-sinx) ^ 2 = 4 - 2 cos ^ 2x #?</h1>
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<p class="gt-block">Versuche dies:<br />
<img alt="Bildquelle hier eingeben" src="https://d2jmvrsizmvf4x.cloudfront.net/vXuVt22JRjiclUDevx6G_Trig2_1.jpg" /> </p>
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		<title>Wie findet man # sin ^ -1 (cos (pi / 6)) #?</title>
		<link>https://dieklugeeule.com/wie-findet-man-sin-1-cos-pi-6/</link>
		
		<dc:creator><![CDATA[Laurene]]></dc:creator>
		<pubDate>Thu, 27 Feb 2020 17:55:10 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=4627</guid>

					<description><![CDATA[Wie findet man # sin ^ -1 (cos (pi / 6)) #? Antworten: #color(blue)(sin^-1 (cos (pi/6)) = pi/3 " or " 60^@# Erläuterung: #"Let " theta = sin^-1 (cos (pi/6))# Aus der Tabelle oben #cos (pi/6) = (sqrt3/2)# #:. theta = sin^-1 (sqrt3/2)# #sin theta = sqrt3/2# Aber #sin 60 = sqrt3/2# wie in der ... <a title="Wie findet man # sin ^ -1 (cos (pi / 6)) #?" class="read-more" href="https://dieklugeeule.com/wie-findet-man-sin-1-cos-pi-6/" aria-label="Mehr dazu unter Wie findet man # sin ^ -1 (cos (pi / 6)) #?">Weiterlesen</a>]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie findet man # sin ^ -1 (cos (pi / 6)) #?</h1>
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<p>#color(blue)(sin^-1 (cos (pi/6)) =  pi/3 " or " 60^@#</p>
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<p><img alt="www.math-only-math.com/images/trigonometrical-ratios-table.png" src="https://d2jmvrsizmvf4x.cloudfront.net/Rod2GhDAR8qhxzUwIaKk_trigonometry+values.png" /> </p>
<p>#"Let " theta = sin^-1 (cos (pi/6))#</p>
<p>Aus der Tabelle oben #cos (pi/6) = (sqrt3/2)#</p>
<p>#:. theta = sin^-1 (sqrt3/2)#</p>
<p>#sin theta = sqrt3/2#</p>
<p>Aber #sin 60 = sqrt3/2# wie in der Tabelle zu sehen.</p>
<p>Daher #color(blue)(theta = sin ^-1 (sin (60)) = 60^@ " or " pi/3#</p>
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		<title>Wie finden Sie den genauen Wert von #sin (-90) #?</title>
		<link>https://dieklugeeule.com/wie-finden-sie-den-genauen-wert-von-sin-90/</link>
		
		<dc:creator><![CDATA[Laurene]]></dc:creator>
		<pubDate>Wed, 01 Jan 2020 16:44:15 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=1133</guid>

					<description><![CDATA[Wie finden Sie den genauen Wert von #sin (-90) #? Antworten: #sin (-90) = -1# Erläuterung: #sin -90 = sin (360 - 90) = sin 270# Winkel #270^@# ist der dritte Quadrant, in dem nur Sonnenbräune und Babybett positiv sind. Daher #sin 270 = sin (180 + 90) = - sin 90 = -1#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie finden Sie den genauen Wert von #sin (-90) #?</h1>
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<p>#sin (-90) = -1#</p>
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<p><img alt="Bildquelle hier eingeben" src="https://d2jmvrsizmvf4x.cloudfront.net/yBbE4WwbQ3i7oJBifvov_1F3694B1-FA83-4D59-BC2C-FF42C74100BB.png" /> </p>
<p>#sin -90 = sin (360 - 90) = sin 270#</p>
<p>Winkel #270^@# ist der dritte Quadrant, in dem nur Sonnenbräune und Babybett positiv sind.</p>
<p><img alt="Bildquelle hier eingeben" src="https://d2jmvrsizmvf4x.cloudfront.net/fJaLgEpeSBClh16XFAbY_B43AE892-2414-41AA-BC35-EAD7E55D0B94.jpeg" /> </p>
<p>Daher #sin 270 = sin (180 + 90) = - sin 90 = -1#</p>
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