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	<title>Jandy &#8211; Die Kluge Eule</title>
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		<title>Wie bewerten Sie #tan (pi / 6) #?</title>
		<link>https://dieklugeeule.com/wie-bewerten-sie-tan-pi-6/</link>
		
		<dc:creator><![CDATA[Jandy]]></dc:creator>
		<pubDate>Wed, 26 Feb 2020 16:36:33 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=287</guid>

					<description><![CDATA[Wie bewerten Sie #tan (pi / 6) #? Antworten: In Sinus und Cosinus konvertieren ... Erläuterung: #tan(pi/6)=sin(pi/6)/cos(pi/6)=(1/2)/(sqrt3/2)=1/sqrt3=sqrt3/3# hoffe das hat geholfen]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie bewerten Sie #tan (pi / 6) #?</h1>
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<p>In Sinus und Cosinus konvertieren ...</p>
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<p>#tan(pi/6)=sin(pi/6)/cos(pi/6)=(1/2)/(sqrt3/2)=1/sqrt3=sqrt3/3#</p>
<p>hoffe das hat geholfen</p>
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		<title>Wie löst man # S = 2pirh + 2pir ^ 2 # für # h #?</title>
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		<dc:creator><![CDATA[Jandy]]></dc:creator>
		<pubDate>Thu, 09 Jan 2020 18:54:30 +0000</pubDate>
				<category><![CDATA[Algebra]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=10588</guid>

					<description><![CDATA[Wie löst man # S = 2pirh + 2pir ^ 2 # für # h #? Antworten: #h=(S-2pir^2)/(2pir)# Erläuterung: #"isolate the term containing h"# #rArr2pirh=S-2pir^2# #"divide both sides by "2pir# #(cancel(2pir) h)/cancel(2pir)=(S-2pir^2)/(2pir)# #rArrh=(S-2pir^2)/(2pir)#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie löst man # S = 2pirh + 2pir ^ 2 # für # h #?</h1>
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<p>#h=(S-2pir^2)/(2pir)#</p>
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<p>#"isolate the term containing h"#</p>
<p>#rArr2pirh=S-2pir^2#</p>
<p>#"divide both sides by "2pir#</p>
<p>#(cancel(2pir) h)/cancel(2pir)=(S-2pir^2)/(2pir)#</p>
<p>#rArrh=(S-2pir^2)/(2pir)#</p>
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