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	<title>Evvy &#8211; Die Kluge Eule</title>
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		<title>Wie beweist man # 1 + tan ^ 2 (x) = sec ^ 2 (x) #?</title>
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		<dc:creator><![CDATA[Evvy]]></dc:creator>
		<pubDate>Sat, 04 Jan 2020 18:54:32 +0000</pubDate>
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					<description><![CDATA[Wie beweist man # 1 + tan ^ 2 (x) = sec ^ 2 (x) #? Antworten: Siehe Erklärung ... Erläuterung: Ab: #cos^2(x) + sin^2(x) = 1# Teilen Sie beide Seiten durch #cos^2(x)# bekommen: #cos^2(x)/cos^2(x) + sin^2(x)/cos^2(x) = 1/cos^2(x)# was vereinfacht: #1+tan^2(x) = sec^2(x)#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie beweist man # 1 + tan ^ 2 (x) = sec ^ 2 (x) #?</h1>
<div class="answerContainer clearfix">
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<h4 class="answerHeader">Antworten:</h4>
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<div class='markdown'>
<p>Siehe Erklärung ...</p>
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<div class="answerDescription">
<h4 class="answerHeader">Erläuterung:</h4>
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<div class='markdown'>
<p>Ab:</p>
<blockquote class="notranslate">
<p>#cos^2(x) + sin^2(x) = 1#</p>
</blockquote>
<p>Teilen Sie beide Seiten durch #cos^2(x)# bekommen:</p>
<blockquote class="notranslate">
<p>#cos^2(x)/cos^2(x) + sin^2(x)/cos^2(x) = 1/cos^2(x)#</p>
</blockquote>
<p>was vereinfacht:</p>
<blockquote class="notranslate">
<p>#1+tan^2(x) = sec^2(x)#</p>
</blockquote>
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