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	<title>Elvera &#8211; Die Kluge Eule</title>
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		<title>Warum ist sec (pi / 4) = sqrt2?</title>
		<link>https://dieklugeeule.com/warum-ist-sec-pi-4-sqrt2/</link>
		
		<dc:creator><![CDATA[Elvera]]></dc:creator>
		<pubDate>Sat, 07 Mar 2020 16:40:13 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=715</guid>

					<description><![CDATA[Warum ist sec (pi / 4) = sqrt2? Antworten: Warum tut #sec (pi/4) = sqrt2# Erläuterung: #sec ((pi)/4) = 1/(cos (pi/4))# Triggertabelle der Spezialbögen gibt -&#62; #cos (pi/4) = sqrt2/2.# Dafür #sec (pi/4) = 2/sqrt2 = sqrt2#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Warum ist sec (pi / 4) = sqrt2?</h1>
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<h4 class="answerHeader">Antworten:</h4>
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<p>Warum tut #sec (pi/4) = sqrt2#</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p class="gt-block">#sec ((pi)/4) = 1/(cos (pi/4))#<br />
Triggertabelle der Spezialbögen gibt -&gt; #cos (pi/4) = sqrt2/2.#<br />
Dafür<br />
#sec (pi/4) = 2/sqrt2 = sqrt2#</p>
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		<title>Was ist die Quadratwurzel von 63 in einfachster radikaler Form?</title>
		<link>https://dieklugeeule.com/was-ist-die-quadratwurzel-von-63-in-einfachster-radikaler-form/</link>
		
		<dc:creator><![CDATA[Elvera]]></dc:creator>
		<pubDate>Sun, 05 Jan 2020 18:06:31 +0000</pubDate>
				<category><![CDATA[Algebra]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=5764</guid>

					<description><![CDATA[Was ist die Quadratwurzel von 63 in einfachster radikaler Form? Antworten: #3sqrt7# Erläuterung: #sqrt63# #sqrt(9*7)# #sqrt(3*3*7)# #3sqrt7#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Was ist die Quadratwurzel von 63 in einfachster radikaler Form? </h1>
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<p>#3sqrt7#</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p>#sqrt63#</p>
<p>#sqrt(9*7)#</p>
<p>#sqrt(3*3*7)#</p>
<p>#3sqrt7#</p>
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