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	<title>Darcey &#8211; Die Kluge Eule</title>
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		<title>Wie vereinfacht man # (sinX-cosX) ^ 2 #?</title>
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		<dc:creator><![CDATA[Darcey]]></dc:creator>
		<pubDate>Mon, 02 Mar 2020 16:42:00 +0000</pubDate>
				<category><![CDATA[Trigonometrie]]></category>
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					<description><![CDATA[Wie vereinfacht man # (sinX-cosX) ^ 2 #? Antworten: # (sinX-cosX)^2 = 1-sin2X # Erläuterung: # sin^2 A + cos^2 A = 1 # # sin 2A = 2 sin A cos A # # (sinX-cosX)^2 = sin^2 X -2sin X cos X + cos^2 X = 1-2sin XcosX = 1-sin2X #]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie vereinfacht man # (sinX-cosX) ^ 2 #?</h1>
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<p># (sinX-cosX)^2 = 1-sin2X #</p>
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<h4 class="answerHeader">Erläuterung:</h4>
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<p class="gt-block"># sin^2 A + cos^2 A = 1 #<br />
# sin 2A = 2 sin A cos A #</p>
<p># (sinX-cosX)^2 = sin^2 X -2sin X cos X + cos^2 X = 1-2sin XcosX<br />
= 1-sin2X #</p>
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