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		<title>Was ist die Ableitung von # y = ln (1 / x) #?</title>
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		<dc:creator><![CDATA[Corene]]></dc:creator>
		<pubDate>Thu, 09 Jan 2020 18:51:43 +0000</pubDate>
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					<description><![CDATA[Was ist die Ableitung von # y = ln (1 / x) #? #y'=-1/x# Volle Lösung #y=ln(1/x)# This can be solved in two different ways, Erklärung (I) The simplest one is, using logarithm identity, #log(1/x^y)=log(x^-y)=-ylog (x)#, similarly following for problem, #y=-ln(x)# #y'=-(ln(x))'# #y'=-1/x# Erklärung (II) Mit Kettenregel, #y'=(ln(1/x))'# #y'=1/(1/x)*(-1/x^2)=-1/x# #y'=-1/x#]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Was ist die Ableitung von # y = ln (1 / x) #?</h1>
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<blockquote class="notranslate">
<p>#y'=-1/x#</p>
</blockquote>
<p class="gt-block"><strong>Volle Lösung</strong> </p>
<blockquote class="notranslate">
<p>#y=ln(1/x)#</p>
<p>This can be solved in two different ways, </p>
</blockquote>
<p class="gt-block"><strong>Erklärung (I)</strong></p>
<blockquote class="notranslate">
<p>The simplest one is, using logarithm identity,  </p>
<p>#log(1/x^y)=log(x^-y)=-ylog (x)#, similarly following for problem,</p>
<p>#y=-ln(x)#  </p>
<p>#y'=-(ln(x))'#</p>
<p>#y'=-1/x#</p>
</blockquote>
<p class="gt-block"><strong>Erklärung (II)</strong></p>
<p class="gt-block">Mit <a href="https://socratic.org/calculus/basic-differentiation-rules/chain-rule">Kettenregel</a>,</p>
<blockquote class="notranslate">
<p>#y'=(ln(1/x))'#</p>
<p>#y'=1/(1/x)*(-1/x^2)=-1/x#</p>
<p>#y'=-1/x#  </p>
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