<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:wfw="http://wellformedweb.org/CommentAPI/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
	xmlns:slash="http://purl.org/rss/1.0/modules/slash/"
	>

<channel>
	<title>Clarissa &#8211; Die Kluge Eule</title>
	<atom:link href="https://dieklugeeule.com/author/clarissa/feed/" rel="self" type="application/rss+xml" />
	<link>https://dieklugeeule.com</link>
	<description></description>
	<lastBuildDate>Fri, 17 Jan 2020 17:41:46 +0000</lastBuildDate>
	<language>de-DE</language>
	<sy:updatePeriod>
	hourly	</sy:updatePeriod>
	<sy:updateFrequency>
	1	</sy:updateFrequency>
	<generator>https://wordpress.org/?v=6.0.2</generator>

<image>
	<url>https://dieklugeeule.com/wp-content/uploads/2022/04/cropped-logo-smal-2-32x32.jpg</url>
	<title>Clarissa &#8211; Die Kluge Eule</title>
	<link>https://dieklugeeule.com</link>
	<width>32</width>
	<height>32</height>
</image> 
	<item>
		<title>Was wäre die Zahnformel eines 16-jährigen Jungen?</title>
		<link>https://dieklugeeule.com/was-ware-die-zahnformel-eines-16-jahrigen-jungen/</link>
		
		<dc:creator><![CDATA[Clarissa]]></dc:creator>
		<pubDate>Fri, 17 Jan 2020 17:41:46 +0000</pubDate>
				<category><![CDATA[Anatomie und Physiologie]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=3279</guid>

					<description><![CDATA[Was wäre die Zahnformel eines 16-jährigen Jungen? Antworten: See below.... Erläuterung: You asked about the question, right but the answer will not be appropriate for all. We know that the dental formula of an adult is #color(red)("I"-2;" C"-1" PM"-2;" M"-3# For a child, it is #color(red)("I"-2;" C"-1" PM"-0;" M"-2# I will say that a #16#-year-old ... <a title="Was wäre die Zahnformel eines 16-jährigen Jungen?" class="read-more" href="https://dieklugeeule.com/was-ware-die-zahnformel-eines-16-jahrigen-jungen/" aria-label="Mehr dazu unter Was wäre die Zahnformel eines 16-jährigen Jungen?">Weiterlesen</a>]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Was wäre die Zahnformel eines 16-jährigen Jungen?</h1>
<div class="answerContainer clearfix">
<div class='answerText'>
<div class="answerSummary">
<h4 class="answerHeader">Antworten:</h4>
<div>
<div class='markdown'>
<blockquote class="notranslate">
<p>See below....</p>
</blockquote>
</div></div>
</p></div>
<div class="answerDescription">
<h4 class="answerHeader">Erläuterung:</h4>
<div>
<div class='markdown'>
<blockquote class="notranslate">
<p>You asked about the question, right but the answer will not be appropriate for all. </p>
<blockquote class="notranslate">
<ul>
<li>
<p>We know that the dental formula of an adult  is #color(red)("I"-2;" C"-1" PM"-2;" M"-3#</p>
</li>
<li>
<p>For a child, it is #color(red)("I"-2;" C"-1" PM"-0;" M"-2#</p>
</li>
<li>
<p>I will say that a #16#-year-old boy will have a dental formula like the one of an adult.</p>
</li>
</ul>
</blockquote>
</blockquote>
<p><img alt="https://thesebonesofmine.wordpress.com/category/tooth/" src="https://d2jmvrsizmvf4x.cloudfront.net/J14YvJG8Q7mr4DlDfQxv_Dental_formula_of_adult_and_children.jpg" /> </p>
</div></div>
</p></div>
</p></div>
</p></div>
]]></content:encoded>
					
		
		
			</item>
		<item>
		<title>Wie findest du die Integration von #log x #?</title>
		<link>https://dieklugeeule.com/wie-findest-du-die-integration-von-log-x/</link>
		
		<dc:creator><![CDATA[Clarissa]]></dc:creator>
		<pubDate>Thu, 19 Dec 2019 16:37:44 +0000</pubDate>
				<category><![CDATA[Infinitesimalrechnung]]></category>
		<guid isPermaLink="false">https://dieklugeeule.com/?p=446</guid>

					<description><![CDATA[Wie findest du die Integration von #log x #? Antworten: #int log(x) dx=1/ln(10)(xln(x)-x)+C=x/ln(10)(ln(x)-1)+C# Erläuterung: #int log(x) dx=int ln(x)/ln(10) dx# #=1/ln(10)int ln(x) dx# Verwendung der Integration in Teilstücken : #int f(x)g'(x) dx=[f(x)g(x)]-int f'(x)g(x) dx# Dort : #f(x)=ln(x), f'(x) =1/x,g(x)=x,g'(x)=1# Damit: #int log(x) dx=1/ln(10)(xln(x)-int dx)# Damit:#int log(x) dx=1/ln(10)(xln(x)-x)+C=x/ln(10)(ln(x)-1)+C# Im Allgemeinen #int log_"n"(x) dx=x/ln(n) (ln(x)-1)+C# #n in RR""_+^*# ... <a title="Wie findest du die Integration von #log x #?" class="read-more" href="https://dieklugeeule.com/wie-findest-du-die-integration-von-log-x/" aria-label="Mehr dazu unter Wie findest du die Integration von #log x #?">Weiterlesen</a>]]></description>
										<content:encoded><![CDATA[<h1 class="questionTitle">Wie findest du die Integration von #log x #?</h1>
<div class="answerContainer clearfix">
<div class='answerText'>
<div class="answerSummary">
<h4 class="answerHeader">Antworten:</h4>
<div>
<div class='markdown'>
<p>#int log(x) dx=1/ln(10)(xln(x)-x)+C=x/ln(10)(ln(x)-1)+C#</p>
</div></div>
</p></div>
<div class="answerDescription">
<h4 class="answerHeader">Erläuterung:</h4>
<div>
<div class='markdown'>
<p class="gt-block">#int log(x) dx=int ln(x)/ln(10) dx#<br />
#=1/ln(10)int ln(x) dx#<br />
Verwendung der <a href="https://socratic.org/calculus/techniques-of-integration/integration-by-parts">Integration in Teilstücken</a>  :<br />
#int f(x)g'(x) dx=[f(x)g(x)]-int f'(x)g(x) dx#<br />
Dort : #f(x)=ln(x), f'(x) =1/x,g(x)=x,g'(x)=1#<br />
Damit: #int log(x) dx=1/ln(10)(xln(x)-int dx)#<br />
Damit:#int log(x) dx=1/ln(10)(xln(x)-x)+C=x/ln(10)(ln(x)-1)+C#</p>
<p>Im Allgemeinen #int log_"n"(x) dx=x/ln(n) (ln(x)-1)+C#</p>
<p>#n in RR""_+^*#    #{1}#,  #C in RR#</p>
</div></div>
</p></div>
</p></div>
</p></div>
]]></content:encoded>
					
		
		
			</item>
	</channel>
</rss>
